I am using malsups form.js to run a login script combined with the zoo visitor add-on. When the login form has been successful the user is successfully logged in with out any need of a page refresh, although when I want to display the username the page needs to be refreshed for those details to appear on screen. Below is my code, any suggestions ?


                        <div class="username_wrap">


dataType: "json", success: function (event) {

                if (event.success) {
                    member_favourites = "5";
                    //do something

2 Answers 2


Create a hidden template that is just the logged in username only. Then load it in via jquery ajax .load(); Once login is complete as well.

               if (event.success) {
                    member_favourites = "5";
                    //do something
  • Champion! appreciate that
    – Sam Crowe
    Mar 29, 2014 at 20:04
  • Glad to help holler if you need anything else @buildmidwestern Mar 29, 2014 at 20:13

With this code it's working fine:

                dataType: 'json',
                success: function(data) {
                    if (data.success) {
                        $("#jqxwindow ").jqxWindow({ height:150,
                                                    width: 250,
                                                    theme: 'bootstrap',
                                                    content: 'Você é registrado',
                                                    resizable: false
                        $('#jqxwindow').on('close', function (event) {
                            alert("You closed a window");

                    } else {
                        alert('Failed with the following errors: '+data.errors.login);

Your code is in the header or footer?? If footer, you have to wrap it with document ready:

$( document ).ready(function() {

the code here


In the example code, the box message are from the Jqx framework , but with a simple js alert box it will work too.

  • Hi Stephane, yes that example does work in regards to showing if an ajaxForm is working, although i need to know how to change the zoo visitor details after a user logs in asynchronously. Hope that makes sense. User still needs to refresh the page to see the visitor:details
    – Sam Crowe
    Mar 29, 2014 at 0:15

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