Template Routes

Question

I'm using EE 3.0.5.

I have a template: store/location

If there's a third segment, additional information is displayed via a conditional: store/location/coupon

The template route is set to: /location/{coupon:alpha_dash} Require all Segments? = NO

But when I try to access /location, I get a 404 Error.

With the additional segment, /location/coupon, everything works fine.

How do I display the template without the last segment, /location? Shouldn't Require all Segments? = NO allow the url without the last segment?

Thanks for your help.

Does your store/location template contain any {redirect="404"} tags? — Derek Hogue, Dec 24, 2015 at 16:12

Yuri Salimovskiy · Accepted Answer · 2015-12-25 17:03:47Z

0

It might be related not to Routes, but to template/URL rules in general.

If in your template preferences you have enabled 'Strict URLs' then at least 2 URL segments are required.

You can try overriding this by adding special route for /location

answered Dec 25, 2015 at 17:03

Yuri Salimovskiy♦

2,8461 gold badge12 silver badges22 bronze badges

I think it is due to the Strict URLs and requiring 2 segments. Thanks for your help.
– atomicglue
Dec 28, 2015 at 3:25

Add a comment |

1 Answer 1