Use if status safecracker

Question

I want to show or hide the status option based on the current status in a safecracker form. This because i want that people can edit statuses form entries which are open or closed, but not the one who are denied.

So far no success because safecracker doesn't like the IF statement, i think i can do it with jquery but is there a good EE solution to get the result i want?

{exp:safecracker 
     channel="nieuws" 
     return="profiel/nieuws" 
     entry_id={segment_3}"
     author_only="yes" 
     error_handling="inline" 
     status="open|closed|denied"}

{if status=="denied"}
    Can't change the status
{if:else}
    <label for="status">Status</label>
    <select name="status" id="status">
        <option value="open">Open</option>
        <option value="closed">Closed</option>
    </select>
{/if}

Answer 1

You can try what Anna suggested. While editing an entry via Safecraker, its populate all the variables of channel entries within safecraker tag so {status} variable also be populated as well.

Also, while looking at your code it seems that you are missing opening double quote while passing parameter entry_id.

Check it.

Answer 2

Try this instead;

{if "{status}" =="denied"}
    Can't change the status
{if:else}
    <label for="status">Status</label>
    <select name="status" id="status">
        <option value="open">Open</option>
        <option value="closed">Closed</option>
    </select>
{/if}